Statements:
All M are K.
All K are J.
All L are J.
No L is a P.
Conclusions:
I. No K is L.
II. Some K are L.
III. Some J are M.
IV. Some L are M.
All K are J(A) + Some J are L(I) ⇒ No conclusion. Hence conclusion I and II does not follow but they will make a complementary pair. Hence either conclusion I or II follows. All M are K(A) + All K are J(A) ⇒ All rose are marigold(A) ⇒ Conversion ⇒ Some J are M(I). Hence conclusion III follows. All M are K(A) + All K are J(A) ⇒ All M are J(A) + Some J are L(I) ⇒ No conclusion. Hence conclusion IV does not follow.
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