How many coins does Q’s have?

Q’s brother M, sits on the immediate left of his mother who has 16 coins. J is the father of P and only one person sits between Q’s mother and N. O, who is sister of P, has 17 coins and is not an immediate neighbour of Q’s husband. P is father of L and is not an immediate neighbour of N. J is married to Q. By the statement ‘only one person sits between Q’s mother and N’, we find that K is Q’s mother and N is M’ daughter.  No female is an immediate neighbour of K, who sits at the corner of the table. K sits second to the left of Q’s husband who has neither 14 nor 17 coins. Only one person is sitting between J and O. M’s daughter sits second to the right of O and on the immediate left of that person who has 13 coins. N sits on the immediate right of the person who has 12 coins.        M, sits on the immediate left of his mother who has 16 coins. P is not an immediate neighbour of N. So, P can sit at immediate right or immediate left to J. If P sits immediate right to J, and as we know that Q is female so she sit at immediate left to N. We know that P sits second to the right of the person who has 18 coins. By this statement this condition is not possible.  If P sits immediate left to J, so Q will sit at immediate right to J. Then L will sit at immediate left to N. Further P sits second to the right of the person who has 18 coins. It is given that N has 11 coin and that of O is 17. So P will have 14 and J will have 15 coins.