Which of the following combination of person meet with C?

Person who likes perfect square number meet with at least two persons. H likes perfect square number and meet with only two person, that means we have two possible number for H, in case (1) H likes 8, in case (2) H likes 14. E Meet with H but doesn’t likes 20, that means H also meet with E. G likes 10 and meet with all the person, that means G meet with all the person likes prime number. I meet with one person. Sum of numbers liked by I and B is 26, that means only possible combination is (8, 16), as the one who likes perfect square number, must meet with at least two persons and I meet with only one person, thus I likes 16 and B likes 8.  Based on above given information  Case (1) is not valid as B likes 8. Again, we have: The one who likes 20 meet with A. A likes 4 but doesn’t meet with E. As, E doesn’t like 20, that means E must likes 24. The one who likes 24 meet with B, that means E meet with B. A meet with two persons but not with H. D meet with the one who likes 14 but not with E, that means D likes 20 and meet with H. C neither likes 12 nor meet with I, as only remaining persons are those who likes prime number, that means C likes 2 and F likes 12. The one who meet with D also meet with B. As, H meet with atleast two persons and E doesn’t meet with D, thus A meet with B. The one who likes 12 meet with the one who likes lowest number, that means F meet with C. Based on above given information we have final arrangement as follow: