Question
Read the directions carefully and answer the following
question. If in the number ‘ 9887532691 ’, the even digits are shifted to the next digit and the odd digits are shifted to their previous digit. Then how many digits repeat themselves?Solution
The given number is ‘9887532691’. After shifting ‘8996423780’. So, there are two repeating digits. The repeating digits are 8 and 9.
More Number operation Questions
I. p2 – 15p + 56 = 0
II. q2 + 2q – 63 = 0
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
I. 4x² -  15x + 9 = 0
II. 20y² -  23y + 6 = 0
Solve the quadratic equation:
5x² − 13x + 6 = 0
I. 2x2 – 5x - 12 = 0
II. y2 – 11y + 30 = 0
I. 2 x² - 15 + 18 = 0
II. x²- 3 + 2 = 0
...I. 18p²- 21p + 6 = 0   Â
II. 16q² - 24q +9 = 0
I. 99x² + 161 x + 26 = 0
II. 26 y² + 161 y + 99 = 0
Roots of the quadratic equation 2x2 + x – 528 = 0 is
l). p² - 29p + 204 = 0
ll). q² + 4q - 221 = 0
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