Question
A boat covers a certain distance against the stream in 9
hours 36 min and it covers the same distance along the stream in 8 hours. What is the ratio of the speed of the boat in still water to that of the stream?Solution
Let the speed of boat in still water =B and speed of stream =S then Speed of boat in Downstream =B+S, and Time = 8h Speed of boat in Upstream=B-S, Time = 9 h 36min=96/10=48/5h ATQ- 48/5(B-S) =8(B+S)
B-S=10 … (1) B+S=12 … (2) B=11, S=1 Now ratio of boat speed and stream speed = 11:1
- What will come in place of (?), in the given expression.
125% of 96 + 33% of 300 = ? What will come in the place of question mark (?) in the given expression?
√144 X √324 + ? = 83 + 31 X √16

The value of 11 × 11 + 11 ÷ 11 – 11 × 11 + 11 + 11 × 11 – 11 – 11 × 11 is:
√ 225 x 24 - √ 144 x 18 = ?
(64/25)? × (125/512)?-1 = 5/8
Find the simplified value of the following expression:
[{12 + (13 × 4 ÷ 2 ÷ 2) × 5 – 8} + 13 of 8]
40 of 30% of 220 = ? + 790
[(4/3) + (5/6)] of 378 = ?
