Question
A man rows 40 km upstream and 60 km downstream in 8
hours. If the ratio of his upstream speed to downstream speed is 2:3, then find the time required to travel 30 km upstream and 45 km downstream.Solution
ATQ,
Let the upstream and downstream speeds be 2x km/hr and 3x km/hr respectively. So, 40/2x + 60/3x = 8 = 20/x + 20/x = 8 = 40/x = 8 ⇒ x = 5 Required time = 30/2x + 45/3x = 30/10 + 45/15 = 3 + 3 = 6 hours
√1764 + 35 × 8 + 39 = ?2
18% of 200 - 16% of 150 = ?
25% of 30% of 3/5 of 14500 =?
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
7/3 of 4/5 of 15/56 of ? = 83
What will come in place of the question mark (?) in the following expression?
40% of 150 – ?% of 80 = 25% of 400
555.05 + 55.50 + 5.55 + 5 +0.55 = ?
64.5% of 800 + 36.4% of 1500 = (?)² + 38
What will come in the place of question mark (?) in the given expression?
25% of 1280 + (41 × 4) = ?2
Simplify the following expression:
((32)4 - 1)/33×31× (210+1)