Question
A child went 70 m towards East to look for his mother,
then he turned right and went 10 m. After this he turned right and after going 40 m he reached to his aunt’s house. His mother was not there. From there he went 50 m to his North and met his mother. What is the shortest possible distance between the initial point and the point where he met his mother?Solution
By using Pythagoras theorem, AE2 = EF2 + AF2 AE = √((30)^2+(40)²) = √2500 = 50 m
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