Question
The price of sugar having gone down by 20% one can buy
6.4kg more for Rs 512. Find the ratio between the original and the reduced price (per kg)?Solution
Let the original price by Rs x Reduced price = Rs (80x/100) ∴512/(80 x/100) - 512/x = 6.4 ⇒51200/80x - 512/x = 6.4 ⇒640/x - 512/x = 6.4 =>128/x= 6.4 ∴ x = 128/6.4 = 20 Original price = Rs 20 Reduced price = Rs (80/100) × 20 = Rs 16 ∴ Required ratio = 20:16 = 5:4
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 103x² - 470x + 367 = 0
Equation 2: 107y² - 504y + 397 = 0
What is the average salary of 10 officers , if a clerk’s salary is Rs. 15,000?
Statement I: The total salary of 10 officers and 5 clerk is Rs....
I. x2 - 5x - 14 = 0
II. y2 - 16y + 64 = 0
I. 2x2 - 15x + 25 = 0
II. 3y2 - 10y + 8 = 0
I. 81x - 117√x + 40 = 0
II. 81y - 225√y + 136 = 0
I. x²= 961Â
II. y= √961
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer Â
I. 3x² –7x + 4 = 0�...
l. 3x2 + 17x + 24 = 0
II. 2y2 + 15y + 27 = 0
I. 2x² - 12x + 16 = 0  Â
II. 4y² - 8y - 12 = 0  Â
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 4x² - 12x + 9 = 0
Equation 2: 2y² + 10y + 12 = 0
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