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Let the original price by Rs x Reduced price = Rs (80x/100) ∴512/(80 x/100) - 512/x = 6.4 ⇒51200/80x - 512/x = 6.4 ⇒640/x - 512/x = 6.4 =>128/x= 6.4 ∴ x = 128/6.4 = 20 Original price = Rs 20 Reduced price = Rs (80/100) × 20 = Rs 16 ∴ Required ratio = 20:16 = 5:4
I. 5q = 7p + 21
II. 11q + 4p + 109 = 0
I. x2 + 16x + 63 = 0
II. y2 + 2y - 15 = 0
I. 3x² - 22 x + 40 = 0
II. 4y² + 22y + 24 = 0
I. 2x² + 11x + 12 = 0
II. 2y² + 19y + 45 = 0
I. 5x² = 19x – 12
II. 5y² + 11y = 12
I. 2x² - 11x + 12 = 0
II. 12y² + 29y + 15 = 0
I. x³= ((4)5+ (15)³)/(3)4
II. 8y³=(-13)3÷ √1521+ (3y)³
I. 66x² - 49x + 9 = 0
II. 46y² - 37y - 30 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 11x² - 93x + 88 = 0
Equation 2: 13y² + 118y + 93 = 0
I. 2y2 - 15y + 18 = 0
II. 2x2 + 9x - 18 = 0