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ATQ, Speed of train 'A' = (150 ÷ 6) = 25 m/s Let the length of train 'C' be 'x' metres. ATQ; (150 + x) ÷ (25 + 20) = 12 Or, 150 + x = 540 So, 'x' = 540 - 150 = 390 Therefore, length of train 'C' = 390 metres
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