Question
The ratio of the speeds of the train and the man is 4:1.
The length of the train is 650 m and crosses a pole in 1 min 5 seconds. In how much time will the man cross the 210 m long platform?Solution
Let the speed of the train = 4x m/s and speed of the man = x m/s Length of the train = 650m Time taken to cross a pole = 1 min 5 sec = 65 seconds S = D/T => 4x = 650/65 => x = 10/4 = 5/2 Speed of the man = 5/2 m/s Man can cross the 210 m platform in = (210 x 2)/5 = 84 seconds = 1 minutes 24 seconds
I. x2 – 3(x + 5) = -11
II. y2 – 4(y + 2) = -2y
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II. 6x² - 19x + 15 = 0
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II. 10y2 - 29y + 21 = 0
I. 4x² - 21 x + 20 = 0
II. 8y² - 22 y + 15 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 36x + 288 = 0
Equation 2: y² - 36y + 320 = 0
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II. Â (1/(y+1)+ 1/(y+5))=(1/(y+2)+ Â 1/(y+4))
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3x² + 6x - 9 = 0
Equation 2: 2y² - 16y + 32 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 45x + 450 = 0
Equation 2: y² - 48y + 540 = 0�...
 If x satisfies x² – 14x + 40 = 0, find x.
I. 3x2 – 16x + 21 = 0
II. y2 – 13y + 42 = 0
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