Question
The ratio of the speeds of the train and the man is 4:1.
The length of the train is 650 m and crosses a pole in 1 min 5 seconds. In how much time will the man cross the 210 m long platform?Solution
Let the speed of the train = 4x m/s and speed of the man = x m/s Length of the train = 650m Time taken to cross a pole = 1 min 5 sec = 65 seconds S = D/T => 4x = 650/65 => x = 10/4 = 5/2 Speed of the man = 5/2 m/s Man can cross the 210 m platform in = (210 x 2)/5 = 84 seconds = 1 minutes 24 seconds
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