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    Question

    If 78 # 62 = 110 and 42 # 56 = 66, then 65 # 42 =

    '__'?
    A 74 Correct Answer Incorrect Answer
    B 56 Correct Answer Incorrect Answer
    C 62 Correct Answer Incorrect Answer
    D 103 Correct Answer Incorrect Answer

    Solution

    The logic followed here is as follows: Product of 2nd digit of 1st number and 1st digit of 2nd number is added to the 2nd number to get the 3rd number.

    78 # 62 = [(8 X 6) + 62] = [48 + 62] = 110

    42 # 56 = [(2 X 5) + 56] = [10 + 56] = 66

    Similarly, 65 # 42 = [(5 X 4) + 42] = [20 + 42] = 62

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