Question
The average of three numbers is 63. The first number is
twice the second number and is half of the third. Then find the 12.5% of the difference of first and third number.Solution
Let the number be a, b and c respectively. ATQ, a = 2b and a = z/2 a + b + c = 63 x 3 = 189 a + a/2 + 2a = 189 7a/2 = 189 a = 54 b = 54/2 = 27 c = 108 Required answer = 12.5% of (108 – 54) = 12.5% x 54 = 6.75
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