Question
If sin 2A = cos (3A - 60o) , then find the
value of sec 2A.Solution
sin 2A = cos (3A - 60)
When sin P = cos Q, then P + Q = 90o
2A + 3A - 60o = 90o
Or, 5A = 150o
Or, 'A' = 30o
Therefore, sec (2 X 30o) = sec 60o = 2
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