Answer-If sin (2A − 3B) = (1/2) and cos (A + B) = (√3/2), where 0°

Q: Answer-If sin (2A − 3B) = (1/2) and cos (A + B) = (√3/2), where 0° < A, B < 90°, then find the value of ‘A’...

sin 2A 3B 12 Or, sin 2A 3B sin 30 Or, 2A 3B 30 ----------- I And, cos A B 32 Or, cos A B cos 30 Or, A B 30 -------------- II On solving equation I 3 equation II, we get 2A 3B 3 A B 30 3 30 Or, 2A 3B 3A 3B 120 Or, 5A 120 So, A 24

Question

Answer-If sin (2A − 3B) = (1/2) and cos (A + B) = (√3/2), where 0° < A, B < 90°, then find the value of ‘A’...

Accepted Answer

sin 2A  3B  12  Or, sin 2A  3B  sin 30  Or, 2A  3B  30 ----------- I   And, cos A  B  32  Or, cos A  B  cos 30  Or, A  B  30 -------------- II   On solving equation I  3  equation II, we get  2A  3B  3  A  B  30  3  30  Or, 2A  3B  3A  3B  120  Or, 5A  120  So, A  24

If sin (2A − 3B) = (1/2) and cos (A + B) = (√3/2),

Solution