Question
If sin (2A − 3B) = (1/2) and cos (A + B) = (√3/2),
where 0° < A, B < 90°, then find the value of ‘A’.Solution
sin (2A − 3B) = (1/2)
Or, sin (2A − 3B) = sin 30°
Or, 2A − 3B = 30° ----------- (I)
And, cos (A + B) = (√3/2)
Or, cos (A + B) = cos 30°
Or, A + B = 30° -------------- (II)
On solving equation I + 3 × equation II, we get;
2A − 3B + 3 × (A + B) = 30 + 3 × 30
Or, 2A − 3B + 3A + 3B = 120°
Or, 5A = 120°
So, ‘A’ = 24°
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
24.11 × 5.98 + 25.03 × 3.12 – 34.99 + 96.9 × 5.02 =?
A salesman is allowed 32% commission on the total sales by him and a bonus of 3% on the sales over Rs. 15000. If the total earnings of a salesman is Rs....
12.052 + 36.15 × 25.45 – 124.15 × 15.05 = ? × 8.08 – 64.32 × 15.98
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What is the value of "π"
25.22 of 359.98% + 499.99 ÷ 25.18 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
? = 19.89% of (29.89 × 12.44) + 9.96 × 12.022
