Question
If area of similar triangles ∆ ABC and ∆ DEF be 64
sq Cm and 121 sq cm and EF = 15.4 cm then BC equalsSolution
We know that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. Here it is given that ΔABC ~ ΔDEF Given, EF = 15.4 cm Therefore, Area of ΔABC / Area of ΔDEF = (BC)2/(EF)2 64 cm2/ 121 cm2 = (BC)2/(15.4)2 (BC)² = [(15.4)2 × 64]/121 BC = (15.4 × 8)/11 BC = 11.2 cm
I. 7x + 8y = 36
II. 3x + 4y = 14
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 2x² - 8x + 6 = 0
Equation 2: y² - 7y + 10 = 0
- What should be the value of t in the equation x² + tx + 64 = 0 so that it has two equal real roots?
I. 2x² - 9x + 10 = 0
II. 3y² + 11y + 6 = 0
If the roots of the quadratic equation 7y² + 5y + 9 = 0 are α and β, then find the value of [(1/α) + (1/β)].
If x² + 2x + 9 = (x – 2) (x – 3), then the resultant equation is:
I. x² - 19x + 84 = 0
II. y² - 25y + 156 = 0
I. 3x2 – 17x + 10 = 0
II. y2 – 17y + 52 = 0
I. 3p² - 14p + 15 = 0
II. 15q² - 34q + 15 = 0
I. 27x² + 120x + 77 = 0
II. 56y² + 117y + 36 = 0
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