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    Question

    If area of similar triangles ∆ ABC and ∆ DEF be 64

    sq Cm and 121 sq cm and EF = 15.4 cm then BC equals
    A 8 cm Correct Answer Incorrect Answer
    B 18 cm Correct Answer Incorrect Answer
    C 11.2 cm Correct Answer Incorrect Answer
    D 8.2 cm Correct Answer Incorrect Answer

    Solution

    We know that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. Here it is given that ΔABC ~ ΔDEF Given, EF = 15.4 cm Therefore, Area of ΔABC / Area of ΔDEF = (BC)2/(EF)2 64 cm2/ 121 cm2 = (BC)2/(15.4)2 (BC)² = [(15.4)2 × 64]/121 BC = (15.4 × 8)/11 BC = 11.2 cm

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