Question
If area of similar triangles ∆ ABC and ∆ DEF be 64
sq Cm and 121 sq cm and EF = 15.4 cm then BC equalsSolution
We know that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. Here it is given that ΔABC ~ ΔDEF Given, EF = 15.4 cm Therefore, Area of ΔABC / Area of ΔDEF = (BC)2/(EF)2 64 cm2/ 121 cm2 = (BC)2/(15.4)2 (BC)² = [(15.4)2 × 64]/121 BC = (15.4 × 8)/11 BC = 11.2 cm
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