If area of similar triangles ∆ ABC and ∆ DEF be 64 sq Cm and 121 sq cm and EF = 15.4 cm then BC equals

We know that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. Here it is given that ΔABC ~ ΔDEF Given, EF = 15.4 cm Therefore, Area of ΔABC / Area of ΔDEF = (BC)^{2}/(EF)^{2} 64 cm^{2}/ 121 cm^{2} = (BC)^{2}/(15.4)^{2} (BC)² = [(15.4)^{2} × 64]/121 BC = (15.4 × 8)/11 BC = 11.2 cm

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