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Start learning 50% faster. Sign in nowWe know that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. Here it is given that ΔABC ~ ΔDEF Given, EF = 15.4 cm Therefore, Area of ΔABC / Area of ΔDEF = (BC)2/(EF)2 64 cm2/ 121 cm2 = (BC)2/(15.4)2 (BC)² = [(15.4)2 × 64]/121 BC = (15.4 × 8)/11 BC = 11.2 cm
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