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      Question

      A train 180 metres long crosses a pole in 12 seconds. If

      its speed increases by 20%, then in how many seconds will it cross a platform 270 metres long?
      A 22 secs Correct Answer Incorrect Answer
      B 25 secs Correct Answer Incorrect Answer
      C 18 secs Correct Answer Incorrect Answer
      D 32 secs Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

      Original speed = 180/12 = 15 m/s After 20% increase, new speed = 15 x 120/100 = 18 m/s To cross a platform of 270 m, total distance = 180 + 270 = 450 m Time = 450/18 = 25 seconds Hence, the correct answer is 25 seconds.

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