Question
Two trains βAβ and βBβ started from station
βPβ and βQβ towards station βQβ and βPβ respectively at the same time. When they met after 11 hours, train βBβ has travelled 144 km more than train βAβ. Find the distance travelled by train βAβ in 8 hours if distance between both stations is 408 km.Solution
Let distance travelled by train βAβ at the time of meet = βxβ km So, distance travelled by train βBβ at the time of meet = βx + 144β km According to question; x + x + 144 = 408 => 2x = 264 => x = 132 Distance travelled by train βAβ in 11 hours = 132 km Speed of train βAβ = 132/11 = 12 km/h Distance travelled by train βAβ in 8 hours = 12 Γ 8 = 96 km
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