Question
Two trains ‘A’ and ‘B’ started from station
‘P’ and ‘Q’ towards station ‘Q’ and ‘P’ respectively at the same time. When they met after 12 hours, train ‘B’ has travelled 120 km more than train ‘A’. Find the distance travelled by train ‘A’ in 10 hours if distance between both stations is 708 km.Solution
Let distance travelled by train ‘A’ at the time of meet = ‘x’ km So, distance travelled by train ‘B’ at the time of meet = ‘x + 120’ km According to question; x + x + 120 = 708 => 2x = 588 => x = 294 Distance travelled by train ‘A’ in 12 hours = 294 km Speed of train ‘A’ = 294/12 = 24.5 km/h Distance travelled by train ‘A’ in 10 hours = 10 × 24.5 = 245 km
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