Question
Two trains βAβ and βBβ started from station
βPβ and βQβ towards station βQβ and βPβ respectively at the same time. When they met after 12 hours, train βBβ has travelled 120 km more than train βAβ. Find the distance travelled by train βAβ in 10 hours if distance between both stations is 708 km.Solution
Let distance travelled by train βAβ at the time of meet = βxβ km So, distance travelled by train βBβ at the time of meet = βx + 120β km According to question; x + x + 120 = 708 => 2x = 588 => x = 294 Distance travelled by train βAβ in 12 hours = 294 km Speed of train βAβ = 294/12 = 24.5 km/h Distance travelled by train βAβ in 10 hours = 10 Γ 24.5 = 245 km
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