Question
A train covers a distance in 6 hours. If speed is
increased by 10 km/h, time reduces by 30 minutes. Find original speed.Solution
ATQ,
Let original speed = v Distance = 6v New time = 5.5 hours So 6v = (v + 10) × 5.5 6v = 5.5v + 55 0.5v = 55 v = 110 Answer: 110 km/h
(749.98% of 639.897) ÷ 23.97 = ?2 - 279.98% of 19.99
The equation of a hyperbola whose conjugate axis equals its transverse axis is:
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