Question
A person walks at 5 km/h for some time and then
increases his speed to 8 km/h, covering a total distance of 39 km in 6 hours. For how much time did he walk at the faster speed?Solution
ATQ, Let time at 5 km/h be t hours Then time at 8 km/h = 6 − t hours Total distance: 5t + 8(6 − t) = 39 5t + 48 − 8t = 39 −3t = −9 ⇒ t = 3 hours So time at 8 km/h = 6 − 3 = 3 hours.
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