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    Question

    Train C leaves Jaipur at a certain time. After 2 hours,

    Superfast Express leaves the same station and travels in the same direction at the speed of 120 km/h. If Superfast Express catches up Train C in 4 hours, then what is the speed of Train C?
    A 90 km/h Correct Answer Incorrect Answer
    B 80 km/h Correct Answer Incorrect Answer
    C 100 km/h Correct Answer Incorrect Answer
    D 85 km/h Correct Answer Incorrect Answer

    Solution

    Distance travelled by Superfast Express in 4 hours = 120 × 4 = 480 km
    Speed of Train C = 480 / (2 + 4) = 80 km/hr

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