Question
1800 metres long train crosses a man who is moving in
the same direction with a certain speed, in 18 seconds. If the same train can cross a tree in 9 seconds with the same speed, then find the speed of the man.Solution
Speed of train = 1800/9 = 200 m/sec Let the speed of the man be βsβ m/sec Relative speed of the train = (200 β s) m/sec According to the question, (200 β s) = 1800/18 Or, s = 200 β 100 = 100 Therefore, speed of the man = 100 m/sec
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