Question
A 420 m long train crosses a platform thrice its length
in 2 min. Find the speed of the train. TYPE 2Solution
Speed of train = (Length of train + Length of Platform)/Required time Length of train = 420 m Crossing time of platform = 2 Γ 60 = 120 sec Length of platform = 420 Γ 3 = 1260 m Let the speed of train be x. Speed of train = (420 + 1260)/120 β Β x = 1680/120 = 14 m/s
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