Question
A goods train leaves a station at a certain time and at
a fixed speed. After 11 hours, an express train leaves the same station and moves in the same direction at a uniform speed of 126 km/hr, this train catches up the goods train in 7 hours. Find the speed of the goods train.Solution
Let the speed of the goods train be ‘s’ km/hr Distance covered by goods train in 18 hrs = s x 18 km Distance covered by express train in 7 hrs = 7 x 126 km Distance covered by goods train in 18 hrs = Distance covered by express train in 7 hrs So, 18s = 7 × 126 ⇒ 18s = 882 ⇒ s = 882/18 = 49 So, Speed of goods train = 49 km/hr
(1.01) 0 + (2.02) 1 + (2.93) 2 + (4.04) 3 + (5.05) 4 = ?
49.97% of 2016 – 37.99% of 1050 = ? – 47.98% of 5950
124.88% of 60.101 + 18.09% of 849.87 – 22.12% of 1049.93= ? – 19.93
(√4623.9 + √484.2) – √2303.97 ÷ √1296.4 × √35.98 ÷ √15.99 = ?
√ ({(5.5 × 2.3) × √ (728.91))} = 3(1/7) ÷ ?/28
...111.89 × 4.12 – 504.04 ÷ 2.12 = 170.12 + ?
2 (1/4)% of 7999.78 + {49.77% of 899.71} + √144.14 - 20% of 1499.83 = ?
44.78% of 715.62 + 1785% of 42.98 = ?
(1560.23 ÷ 25.98) + (768.32 ÷ 23.9) + 1814.11 = ?
70.14% of 799.95 - 240.12 = ? + 40.17% of 299.95
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