Question
Karan is five times as efficient as Varun and twice as
efficient as Arjun. If Varun takes 30 days to finish some work, then find the time taken by Karan and Arjun to do the same work together.Solution
Since, Karan is five times as efficient as Varun, he will take one-fifth the time taken by Varun to finish the work. So, time taken by Karan to do the work = 30 ÷ 5 = 6 days And, Karan is twice as efficient as Arjun, so Arjun will take double the time taken by Karan. So, time taken by Arjun to do the work = 2 × 6 = 12 days Let the total work be '12x' units. So, efficiency of Karan = 12x ÷ 6 = '2x' units/day And, efficiency of Arjun = 12x ÷ 12 = 'x' units/day So, required time = 12x ÷ (2x + x) = 4 days Hence, option c.
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