Question
Pawan and Raju can finish a task
in 12 days when working together. The time required for Qureshi, Raju, and Suresh to complete 74% of the work equals the time needed by Qureshi, Raju, and Tina to finish 84% of the same work. Tina is 50% more efficient than Suresh and can complete the entire work alone in 24 days. Additionally, Qureshi, Raju, Suresh, and Tina can collectively complete 78% of the work in 5.4 days. Based on this information, which of the following can be determined? I. The time Pawan alone would take to complete the work. II. The time Qureshi and Raju together would take to complete the work. III. The time Suresh and Pawan together would take to complete the work. IV. The time Qureshi alone would take to complete the work. V. None of the above.Solution
ATQ, Time taken by Tina alone = 24 days Time taken by Suresh alone = 24 × 1.5 = 36 days Pawan & Raju --->  12            6 Tina         ----> 24   } 72 {     3 Suresh       ----> 36            2 Efficiency of Qureshi & Raju = (72 × 0.78)/5.4 - (3 + 2) = 10.4 - 5 = 5.4 Individual efficiency of Pawan, Qureshi & Raju cannot be determined hence Time taken by Qureshi & Raju together to complete the work = 72/5.4 = 13.33 days Hence, Only II statement is possibleÂ
41.66% of 888 + 66.66% of 1176 = ?2 - 4√ 16 Â
Evaluate: 320 − {18 + 4 × (21 − 9)}
Simplify: 72 ÷ 6 × 3 − 8 + 4
118 × 6 + 13 + 83 = ?
Simplify the following expression:
  (400 +175) ² - (400 – 175) ² / (400 × 175)
150% of 850 ÷ 25 – 25 = ?% of (39312 ÷ 1512)
(75 + 0.25 × 10) × 4 = ?2 - 14
26% of 650 + 15% of 660 – 26% of 450 = ?
115% of 40 + 3 × 4 = ? × 11 – 8