Question
In the figure given below, AC = 16 cm and BF = 5 cm. If
AE:CE = 5:3, then find the perimeter of ΔABC.Solution
AE = (5/8) X 16 = 10 cm
CE = 16 - 10 = 6 cm
Length of tangents drawn from an external point to a circle is equal.
So, AF = AE = 10 cm
And, CD = CE = 6 cm
And, BD = BF = 5 cm
Required perimeter = 10 + 6 + 6 + 5 + 5 + 10 = 42 cm
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