Question
What will be inradius of a right angle triangle whose
base is 11 cm & height is 60 cm ?Solution
By pythogorus theorem, Hypotenuse 2 = Base 2 +Height 2 = 112 + 602 = 121 + 3600 = 3721, So Hypotenuse = 61; Now inradius of a right angle triangle = (Base + Height - Hypotenuse)/2 = (11 + 60 - 61)/2 = 10/2 = 5 cm
Find the area of triangle having sides 5 m, 6 m, and 9 m.
∆ABC and ∆DEF are similar and their areas are respectively 49cm2 and 64cm 2 . If EF = 12 cm BC is?
AB is the diameter of a circle with centre 'O'. PQ is a chord that cuts AB at 'C'. If radius of the circle is 7.5 cm and AC:CB = 3:2, the find the lengt...
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If O is circumcentre of acute angled triangle ABC, if ∠ BOC = 150˚ then ∠ BAC = ?
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The measure of an angle is one-third of its supplementary angle. Find its measure.
If G is the centroid and AD, BE, CF are three medians of ∆ABC with area 54 cm 2 , then the area of ∆BGD is?
If I is the incentre of ΔABC , if ∠ BIC = 112.5° , then what is the measure of ∠ BAC?
