In Fig. if QT ⊥ PR, ∠ TQR = 40 ° and ∠ SPR = 30 ° , find x and y.
In ∆ TQR, 90° + 40° + x = 180°(Angle sum property of a triangle) Therefore, x = 50° Now, y = ∠ SPR + x (ext. angle equal to sum of opp. int angles) Therefore, y = 30° + 50° y = 80°
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