Question
Akash can finish a task alone in
24 days, while Akash and Bittu working together can complete the same task in 14 days. If Bittu starts the work alone and stops after 19.6 days, how many days will Akash need to finish the remaining work by himself?Solution
ATQ,
Let the total work = L.C.M of 24 and 14 = 168 units So, efficiency of ‘Akash’ alone = 168 ÷ 24 = 7 units/day Combined efficiency of ‘Akash’ and ‘B’ = 168 ÷ 14 = 12 units/day So, efficiency of ‘Bittu’ alone = 12 – 7 = 5 units/day Work completed by ‘Bittu’ alone in 19.6 days = 19.6 × 5 = 98 units Time taken by ‘Akash’ alone to complete the remaining work = (168 – 98) ÷ 7 = 10 day
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