Question
How many four-letter words without repetition having
exactly two vowels can be formed by using the letters of the word "MISTAKE"?Solution
"MISTAKE" has 4 consonants and 3 vowels.
Number of ways to select the letters = 3C2 × 4C2 = 3 × 6 = 18
Arrangements of 4 letters = 4! = 24
Total number of words formed = 18 × 24 = 432
351Â Â Â 261Â Â Â 181Â Â Â 111Â Â Â 51Â Â Â ?
Find the 31st term of the series 25, 29, 33……
632, 560, 494, 434, ?, 332
1331      1000            729       512       ?             216
...2556   636    156    ?    6
3 5 15 75 1125 ?
...1. In series II, if ‘x’ is the right term, then find which of the following statement(s) are true.
I. x/124 is a factor 6 and 8.
73920, 9240, ?, 220, 44, 11
12 78 385 ? 4629 9260
...A number series is given below, which follows a specific pattern. If 'A' represents the 'x'th term and 'B' represents ...
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