Question
Nikhil and Rohit together can complete a job in 105 days
8 minutes, while Rohit and Suresh together can finish the same job in 70 days 5 minutes. If Suresh’s efficiency is 24.99% less than Rohit's, find the approximate time taken by all three to complete 80% of the job together.Solution
ATQ Let the efficiency of Rohit be '6x' units/day So, efficiency of Suresh = 0.75 x 6x = '4.5x' units/day So, total work = (6x + 4.5x) x 70 = '735x' units So, combined efficiency of Nikhil and Rohit = (735x / 105) = '7x' units/day Therefore, required time = [(735x x 0.8) ÷ (6x + 4.5x) ] = 56 days
More Time and work Questions
- Which letter and number cluster will replace the question mark (?) to complete the given series?
LT6, KU12, IW24, FZ48, ____ - A series is given with one term missing. Choose the correct alternatives from the given ones that will complete the series.
57, 59, 56, 61, 54, ___ - Which letter-cluster will replace the question mark (?) in the following series?
RGV, UME, ?, AYW, DEF - Select the number from among the given options that can replace the question mark (?) in the following series.
17, 18, 22, 31, 47, ___ - Which letter-cluster will replace the question mark (?) in the following series?
NPQR, OORQ, PNSP, ____, RLUN
Relevant for Exams:
