Question
Nikhil and Rohit together can complete a job in 105 days
8 minutes, while Rohit and Suresh together can finish the same job in 70 days 5 minutes. If Suresh’s efficiency is 24.99% less than Rohit's, find the approximate time taken by all three to complete 80% of the job together.Solution
ATQ Let the efficiency of Rohit be '6x' units/day So, efficiency of Suresh = 0.75 x 6x = '4.5x' units/day So, total work = (6x + 4.5x) x 70 = '735x' units So, combined efficiency of Nikhil and Rohit = (735x / 105) = '7x' units/day Therefore, required time = [(735x x 0.8) ÷ (6x + 4.5x) ] = 56 days
What will be the output of the code
int main(){
int x= 10;
int y=10;
int s=-(-x-y)
cout<
return 0;
}
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