Question
A can complete a work in 15 days. B takes 6 days less
than A to complete the same work. In how many days can both of them together complete 80% of the work together?Solution
Time taken by B to complete the work = 15 – 6 = 9 days Let the total work = 45 units Efficiency of A = 45/15 = 3 units/day Efficiency of B = 45/9 = 5 units/day Required time taken = 0.80 x 45/(3+5) = 4.5 days
Statements: L < E; M = O; E >K ≥ M
Conclusions:
I. L < M
II. K = O
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