Question
A and B together, B and C together and A and C
together can complete a piece of work in 10 days, 11 days and 16 days respectively. Find the ratio of the efficiencies of A, B and C, respectively.Solution
Let, the total work be 880 units (LCM of 10, 11 and 16)
Amount of work done by A and B together in one day = 880/10 = 88 units
Amount of work done by B and C together in one day = 880/11 = 80 units
Amount of work done by A and C together in one day = 880/16 = 55 units
Amount of work done by A, B and C together in one day = (88 + 80 + 55)/2 = 111.5 units
Amount of work done by A alone in one day = 111.5 – 80 = 31.5 units
Amount of work done by B alone in one day = 111.5 – 55 = 56.5 units
Amount of work done by C alone in one day = 111 – 88 = 23.5 units
So the desired ratio = 63:113:47
More Time and work Questions
√324 * 6 – 20% of 180 + ? = 130% of 150
What is the value of 143 + 163 + 183 + … + 303?
(2/?) x (3/16) x (2/15) x 60 = 1/3


154 × 7 + 480 × 5 =?% of 6956
- What will come in the place of question mark (?) in the given expression?
40% of (320 ÷ 4) + 2² X 25 = ? + 42 (5/8 of 480 - 30% of 420)² ÷ (√81 + 25% of 320) = ?
17% of 250 + ? = 108
Simplify the following expression and find the final value:
(18 ÷ 6 of 2 + 7 of 5) ÷ 5