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Let the total journey be = 5/8, 6/7, LCM of the denominator = 56 km At 11.30 am, Peter covers 5/8 of the whole journey i.e., 56 × 5/8 = 35km At 6.00 pm, Peter covers 6/7 of the whole journey i.e., 56 × 6/7 = 48 km Therefore, Peter covers (48 - 35) = 13 km in (6.00 pm – 11.30am) = 6*1/2 hours. Then the speed of a Peter = `13/(6(1/2)` = 2km per hour Time taken by Peter to cover 35 km = 35/2 hours = `17(1/2)` hours Then the starting time of the journey is 11.30am - `17(1/2)` hours = 6:00 pm
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