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    Question

    'A' can do some work alone in 16 days. 'A'and 'B' work

    together for 8 days after which'A' leaves and 'B' finishes the remaining work alone in 12 days. How much time does 'B' need to finish the work alone?
    A 40 days Correct Answer Incorrect Answer
    B 30 days Correct Answer Incorrect Answer
    C 45 days Correct Answer Incorrect Answer
    D 25 days Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ, Let the efficiency of 'A' be 'a' units/day. So, total work = 16 × a = '16a' units So, work done by 'A' in 8 days = a × 8 = '8a'units So, work done by 'B' = 16a - 8a = '8a' units So, efficiency of 'B' = 8a ÷ (12 + 8) = '0.4a'units/day So, required time = 16a ÷ 0.4a = 40 days

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