Answer-Which of the following scenarios violates Boyce-Codd Normal Form (BCNF) in a relational schema?

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BCNF is a stricter version of 3NF. A table is in BCNF if, for every functional dependency XYX , X is a superkey. If a candidate key determines another candidate key, it creates redundancy and violates BCNF. For instance, consider a table where StudentID and CourseID are candidate keys, but CourseID determines StudentID. This means there are multiple possible combinations leading to redundancy.   Why Other Options Are Incorrect    Option A This scenario adheres to both 3NF and BCNF, as all non-key attributes depend only on the primary key.   Option B This violates 2NF due to partial dependency but does not directly address BCNF.   Option C This violates 3NF by allowing transitive dependency but does not necessarily violate BCNF.   Option E This statement is a valid condition for both 3NF and BCNF.

Which of the following scenarios violates Boyce-Codd Normal Form (BCN

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