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    Question

    Two ladies simultaneously leave cities A and B

    connected by a straight road and travel towards each other. The first lady travels 3 km/hr faster than the second lady and reaches B one hour before the second lady reaches A. The two cities A and B are 36 km apart. How many kilometres does each lady travel in one hour?
    A 12 km, 6 km Correct Answer Incorrect Answer
    B 12 km, 9 km Correct Answer Incorrect Answer
    C 8 km,6 km Correct Answer Incorrect Answer
    D 9 km, 14 km Correct Answer Incorrect Answer
    E none of these Correct Answer Incorrect Answer

    Solution

    Let the speed of the second lady = x kmph ∴ Speed of first lady = [if gte msEquation 12]>x [if !msEquation]-->[endif]--> x + 3 kmph ∴ As per the question `36/x - 36/(x +3) = 1` [if gte msEquation 12]> 36 x [if !msEquation]-->[endif]--> ⇒(36x+108-36x)/(x2+3x) = 1 ⇒108=x2+3x ⇒ x ² + 3x - 108 = 0 ∴ [if gte msEquation 12]>x [if !msEquation]-->[endif]--> x ² + 12x [if gte msEquation 12]> x [if !msEquation]-->[endif]--> - 9x [if gte msEquation 12]> x [if !msEquation]-->[endif]--> - 108 = 0 ∴ x(x+12) -9(x-12) = 0 (x+12)(x-9) = 0 ∴ x = -12 or 9 kmph Speed cannot be negative, Hence x = 9kmph So speed of two ladies are = x+3 , x = 12kmph & 9kmph

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