Question
A person travelled a distance of 200 km in 7 hours. He
travelled partly on a car at the speed of 50 kmph and partly on cycle at 20 kmph. What is the distance travelled by him on cycle?Solution
Let the distance travelled by car = x Distance travelled by cycle = 200 – x According to the question, x/50 + (200 - x)/20 = 7 2x + 1000 - 5 x = 700 300 = 3 x x = 100 km/hr. Distance travelled by cycle = 200 – 100 = 100 km/hr.
I. 24x² - 58x + 23 = 0
II. 20y² + 24y – 65 = 0
Solve both equations I & II and form a new equation III in variable ‘r’ (reduce to lowest possible factor) using roots of equation I and II as per ...
I. 64x2 - 64x + 15 Â = 0 Â Â Â Â
II. 21y2 - 13y + 2Â =0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 32x + 207 = 0
Equation 2: y² - 51y + 648 = 0
If a and b are the roots of x² + x – 2 = 0, then the quadratic equation in x whose roots are 1/a + 1/b and ab is
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. y/16 = 4/yÂ
II. x3 = (2 ÷ 50) × (2500 ÷ 50) × 42 × (192 ÷ 12)
The equation q2 - 17x + C = 0, has two roots ‘x’ and ‘y’ such that (x – y) = 7. Find an equation which is equal to thrice of the gi...
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 41x² - 191x + 150 = 0
Equation 2: 43y² - 191y + ...
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 24x + 143 = 0
Equation 2: y² - 26y + 165 = 0
