Two places are 18 km and 30 km away from Akshat and Saksham’s home. They started at the same time and reached their places exactly at 7:00
A.M. Later, their places were exchanged, and Akshat started 24 minutes earlier than Saksham to be on time. Find the speed of Akshat.

ATQ, ATQ, Distance covered by Akshat and Saksham = 18 km and 30 km, respectively Since, both of them reached their respective places at same time Therefore, ratio of speeds of Akshat and Saksham = 18:30 = 3:5 Let the speeds of Akshat and Saksham be 3x km/hr and 5x km/hr, respectively Time taken by Akshat on the day of interchange = 30/(3x) hours Time taken by Saksham on the day of interchange = 18/(5x) hours According to the question, (30/(3x)) – (18/(5x)) = 24/60 Or, (10/x) − (18/(5x)) = 2/5 Or, (50 − 18)/(5x) = 2/5 Or, 32/(5x) = 2/5 Or, 32 = 2x Or, x = 16 Therefore, speed of Akshat = 3x = 48 km/hr