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      Question

      A runner, going at five-sixths of her normal speed, takes

      10 minutes longer than usual to complete a race. What is her usual time?
      A 19 min Correct Answer Incorrect Answer
      B 12 min Correct Answer Incorrect Answer
      C 10 min Correct Answer Incorrect Answer
      D 27 min Correct Answer Incorrect Answer

      Solution

      ATQ,

      Let the usual speed of the runner be '6s' km/h and the distance be 'd' km.

      Let the usual time taken be 't' hours.

      ATQ;

      (d/6s) = t

      Or, d = 6ts ........ (I)

      Now, running at five-sixths of her speed:

      (d/(5s)) = t + (10/60)

      Using equation (I), we have;

      (6ts/5s) = t + (1/6)

      Or, 6t = 5t + (1/6)

      Or, t = (1/6)

      Thus, the usual time taken by the runner to complete the race = (1/6) hours or 10 minutes.

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