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    Question

    I. 2x² - 12x + 16 = 0     II. 4y² - 8y  -

    12 = 0    
    A If x ≥ y Correct Answer Incorrect Answer
    B If x ≤ y Correct Answer Incorrect Answer
    C If x > y Correct Answer Incorrect Answer
    D If x = y or relationship between x and y cannot be established Correct Answer Incorrect Answer

    Solution

    I. 2x² - 12 x + 16 = 0     2x² - 8x - 4x + 16 = 0     2 x (x – 4) – 4 ( x – 4 ) (2 x – 4 ) (x – 4) x = 4, 2 II. 4y² - 8 y  - 12 = 0     4y² - 12y + 4 y - 12 = 0     4 y (y – 3) + 4 ( y – 3 ) (4y + 4 ) (y – 3) y = - 1, 3 Hence relationship between x and y cannot be established.

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