Question
The speed of two cars A and B are in the ratio of 14:17
respectively. Car A travels 12 km less than the car B in the same time duration. What was the distance (in km) travelled by the car B during that time?Solution
Let the speed of car A = 14x km/h and the speed of car B = 17x km/h. Here the time is constant. According to question, => 17x – 14x = 12 => 3x = 12 => x = 4 Distance travelled by car B = 17 × 4 = 68 km
A $ B means A X B, A & B means A - B, A % B means A ÷ B and A # B means A + B, then what is the value of 320 & 80 # 120 % 24 $ 50?
Statements:
V ≤ P < S = B; T < U ≤ I = B; N < J < T
Conclusions:
I. J > P
II. N < S
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