Akshat and Saksham have two delivery points at distances 32 km and 48 km from their house. They left together and reached their points at 9:15
A.M. On another day, the delivery points were swapped, and Akshat started 40 minutes earlier than Saksham to reach on time. Find the speed of Akshat.

ATQ, Distance covered by Akshat and Saksham = 32 km and 48 km, respectively Since, both of them reached their respective places at same time Therefore, ratio of speeds of Akshat and Saksham = 32:48 = 2:3 Let the speeds of Akshat and Saksham be 2x km/hr and 3x km/hr, respectively Time taken by Akshat on the day of interchange = 48/(2x) hours Time taken by Saksham on the day of interchange = 32/(3x) hours According to the question, (48/(2x)) – (32/(3x)) = 40/60 Or, (24/x) − (32/(3x)) = 2/3 Or, (72 − 32)/(3x) = 2/3 Or, 40/(3x) = 2/3 Or, 40 = 2x Or, x = 20 Therefore, speed of Akshat = 2x = 40 km/hr