Question
Tina started running from a park at 10 m/s. 5 seconds after
Tina left, Riya began running from the same spot and managed to catch Tina in 25 seconds. Find Riya’s speed.Solution
ATQ,
Distance covered by Tina in 5 seconds = 10 × 5 = 50 metres
Relative speed between Riya and Tina = 50 ÷ 25 = 2 m/s
Riya is faster.
So, Riya’s speed = 10 + 2 = 12 m/s
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