Question
A bus takes 10 seconds to pass a standing man and 28
seconds to pass a traffic light, which is 405 meters long. Determine the time it takes for the bus to pass a boy running towards it at a speed of 9 km/h.Solution
ATQ, Let the length of the bus be 'x' meters. So according to question:Â x/10 = (x + 405) /28 28x = 10x + 4050 18x = 4050, x = 225 So, the length of the bus = 225 meters Speed of the bus = 225/10 = 22.5 m/s Speed of the boy = 9 X 5/18 = 2.5 m/s Relative speed of the bus = 22.5 + 2.5 = 25 m/s So, the time taken by the bus to cross the boy = 225/25 = 9 seconds
1885 ÷ 64.98 + 7.29 + ? = 69.09
212 + 14 × 23 – 28 × 15 = ? Â
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
567-4824 ÷ 134 =? × 9
Determine the value of 'p' in the expression.
28 ÷ 22p + 1 = 43Â
What will come in place of (?) in the given expression.
(15) ² - (13) ² = ?? = 6.25% of 240 + 25 2 + 17 2 – 16 × 17
35% of 840 + 162 = ? – 25% × 300
(7/5) × (3/4) × (5/9) × (6/7) × 3112 = ?
1024 ÷ 16 + 800 ÷ √64 + ? = 200 * 2