Question
A person travels a certain distance at 8 km/hr and
reaches 1 hr 30 minutes late. If he travels at 10 km/hr, he reaches 1 hr 30 minutes earlier. The distance he has to travel isSolution
Total time difference = 3 hrs. According to the question, D/8 + D/10 = 3 5D – 4D = 3 × 40 D = 120 km Alternate method: Distance = Time gap× product of speeds/ gap of speed = 3 hrs×8×10/(10-8) = 3 hrs ×8×10/2 = 120 Km
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