Question
While jogging at (3/4) of his usual speed, a man reaches the park 15 minutes late. Find his usual jogging time.
Solution
ATQ, When distance is constant, Time ∝ (1 / Speed) Ratio of usual time to new time = 3 : 4 Let usual time = 3t and new time = 4t. 4t – 3t = 15 ⇒ t = 15 Usual time = 3t = 3 × 15 = 45 minutes
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