Question
While jogging at (3/4) of his usual speed, a man reaches
the park 15 minutes late. Find his usual jogging time.Solution
ATQ, When distance is constant, Time ∝ (1 / Speed) Ratio of usual time to new time = 3 : 4 Let usual time = 3t and new time = 4t. 4t – 3t = 15 ⇒ t = 15 Usual time = 3t = 3 × 15 = 45 minutes
More Time and distance Questions
The value of 43-3× (4×6+12/3 ×6-4×5) +4?
13 X ? = 85 X 4 + √81 + 2
What will come in the place of question mark (?) in the given expression?
48 ÷ 4 × (3 + 5) – 6² + 10 = ?
5.45% of 1854 – 37.5% of 1096 = ? – 48% of 630
72% of 486 – 64% of 261 = ?
20% of 450 - 15% of 400 = 25% of ?
56 × 18 + ? × 21 – 49 × 12 = 63 × 26
Simplify the following expressions and choose the correct option.
[(2/3 of 270) ÷ 9] + [(5/6 of 96) ÷ 8] = ?
(21 X 5) + ? = (480 - 120) ÷ 3
Relevant for Exams:
