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    Question

    A cyclist travels from town P to town Q at 12 km/h and

    returns from Q to P by the same route at a speed which is 25% higher. Due to the increase in speed on the return journey, he takes 1 hour less for the entire trip than he would have taken if he had travelled at 12 km/h both ways. What is the distance between P and Q?
    A 60 km Correct Answer Incorrect Answer
    B 80 km Correct Answer Incorrect Answer
    C 40 km Correct Answer Incorrect Answer
    D 50 km Correct Answer Incorrect Answer

    Solution

    ATQ, Let distance = d km. Time if speed is 12 km/h both ways = 2d/12 = d/6 hours. Actual speeds: PтЖТQ: 12 km/h тЗТ time = d/12 QтЖТP: 25% more тЗТ 12 ├Ч 1.25 = 15 km/h тЗТ time = d/15 Actual total time = d/12 + d/15 = (5d + 4d)/60 = 9d/60 = 3d/20 Given: 3d/20 = d/6 тИТ 1 Multiply by 60: 9d = 10d тИТ 60 тЗТ d = 60 km.

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