Question
Tina has to reach the railway station. If she walks at 12
km/h, she is 2 hours late. If she walks at 20 km/h, she reaches 1 hour early. Find the distance between her house and the station.Solution
ATQ,
Let the distance = 'd' km
Let the usual time = 't' hours
Then, (d/12) = t + 2
Or, t = (d/12) - 2
And, (d/20) = t - 1
Or, t = (d/20) + 1
So, (d/12) - (d/20) = 3
LCM of 12 and 20 = 60
Or, (5d - 3d)/60 = 3
Or, 2d = 180
So, d = 90
Therefore, the distance = 90 km
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